How to strip multiple characters/words from a string

I would like to strip out punctuation, and a list of ‘stop words’, from search parameters. Is the only way to do this using a string of replaces:
value.replace(",", "").replace(".", "") etc… ?
As far as I can see there isn’t a formatter which would take a list/array as an argument.

There seems to be a slight bug with this formatter (or perhaps others). When I reenter the formatter options, the final “)” is removed:

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Generally, it’s a bit of a fight using the formatter. If you enter nothing (which is what I actually want), a message pops up saying a field is required:
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If I enter “”, the “” are escaped by Wappler, so the quotes appear in the output (defeating the purpose of using Replace).
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Manually editing the expression solves the problem.